Intermediate

Circle Center Calculator — Find Center & Radius from 3 Points

Enter any three points that lie on a circle to find its center (h, k) and radius — calculated by solving the perpendicular-bisector system.
Radius
2.5000

Distance from center (h, k) to each of the three input points

Center x (h)
2
Center y (k)
1.5
Area (πr²)
19.635
Circumference (2πr)
15.708
Standard equation
(x − 2)² + (y − 1.5)² = 6.25
P₁P₂P₃C
Step by step
  1. 1

    Linear system determinant

    8 × 6 − 0 × 0 = 48
    Non-zero determinant confirms the three points are not collinear.
  2. 2

    Center x (h)

    (16 × 6 − 9 × 0) ÷ 48 = 2
  3. 3

    Center y (k)

    (8 × 9 − 0 × 16) ÷ 48 = 1.5
  4. 4

    Radius = distance from center to P₁

    √((0 − 2)² + (0 − 1.5)²) = 2.5000
Results are estimates for general information only and are not professional advice — always verify important results independently before relying on them. Read the full disclaimer.
Quick answer

How does this calculator work?

Three non-collinear points uniquely fix a circle. Cancel the squared terms in the equal-distance equations to get a 2×2 linear system; solve for center (h, k) by Cramer's rule. Radius = distance from center to any input point. Result is displayed as the standard-form equation and plotted.

Formula
Solve: 2(x₂−x₁)h + 2(y₂−y₁)k = x₂²−x₁²+y₂²−y₁² (and similarly for P₃); then r = √[(x₁−h)²+(y₁−k)²]
How this is calculated

Any three non-collinear points lie on exactly one circle. Its center is equidistant from all three — which is the same as the circumcenter of the triangle they form. Setting the squared distance from an unknown center (h, k) to two pairs of points equal gives a linear equation in h and k each time (the squared terms cancel). Two such equations form a 2×2 system solvable by Cramer's rule.

The calculator computes coefficients a₁, b₁, c₁ from points 1 and 2, and a₂, b₂, c₂ from points 1 and 3, evaluates the determinant, then solves for h and k. The radius is the Euclidean distance from the center to any of the three input points. The result is algebraically exact, aside from floating-point rounding.

If the three points are collinear (all on one line) the determinant is zero — no unique circle exists. Move at least one point off the line to get a valid result.

Frequently asked questions

The circumcenter is the point equidistant from all three vertices of a triangle — it is the center of the circle that passes through (circumscribes) all three vertices. For acute triangles it lies inside; for obtuse triangles it lies outside.

Two points leave one degree of freedom: infinitely many circles of different radii can pass through them. A third point removes that freedom, uniquely fixing both center and radius — provided the points are not collinear.

The points you entered are collinear (all on a straight line). A straight line is a circle of infinite radius. Adjust at least one point so they form a triangle with non-zero area.

Also known as

find center of circle from three points
circumcenter calculator
circumscribed circle center radius
circle center from points calculator
circle through three points calculator
circle equation from coordinates

APA

TG we-Calculate Editorial Team. (2026). Circle Center Calculator — Find Center & Radius from 3 Points [Online calculator]. TG we-Calculate. https://we-calculate.com/calculator/circle-center-calculator

Chicago

TG we-Calculate Editorial Team. "Circle Center Calculator — Find Center & Radius from 3 Points." TG we-Calculate. 2026. https://we-calculate.com/calculator/circle-center-calculator.

IEEE

TG we-Calculate Editorial Team, "Circle Center Calculator — Find Center & Radius from 3 Points," TG we-Calculate, 2026. [Online]. Available: https://we-calculate.com/calculator/circle-center-calculator

BibTeX

@misc{wecalculate_circle_center_calculator, title = {Circle Center Calculator — Find Center & Radius from 3 Points}, author = {{TG we-Calculate Editorial Team}}, howpublished = {\url{https://we-calculate.com/calculator/circle-center-calculator}}, year = {2026}, note = {TG we-Calculate} }

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