Advanced

First-Order Half-Life Calculator

Compute the half-life and remaining concentration of a first-order reaction from its rate constant.

1/s

First-order rate constant (must be positive)

M

Optional starting concentration

s

Optional time to evaluate [A]t
Half-life (t½)
13.8629s

Time for the concentration to fall by half

Rate constant k
0.05 1/s
[A] at time t
0.3679 M
Fraction remaining
36.79 %
Mean lifetime (1/k)
20 s
Concentration decay over ~5 half-lives
Step by step
  1. 1

    ln(2)

    0.6931
    The natural logarithm of 2 appears because the concentration falls by half each half-life.
  2. 2

    Half-life t½ = ln(2) ÷ k

    0.6931 ÷ 0.05 = 13.8629
Results are estimates for general information only and are not professional advice — always verify important results independently before relying on them. Read the full disclaimer.
Quick answer

How does this calculator work?

For a first-order reaction the half-life is t½ = ln(2)/k ≈ 0.693/k and depends only on the rate constant, not the starting amount. The remaining concentration after time t follows [A]t = [A]0·e^(−k·t). Enter k (and optionally [A]0 and t) to get the half-life, remaining concentration, and a decay curve.

Formula
t½ = ln(2) / k = 0.693 / k ; [A]t = [A]0 · e^(−k·t)
How this is calculated

A first-order reaction has a rate that is directly proportional to the concentration of a single reactant. Its half-life depends only on the rate constant k (in inverse seconds), not on the starting concentration, so each successive half-life takes the same amount of time. The half-life is t½ = ln(2)/k ≈ 0.693/k. Enter k to get the half-life directly.

To find how much reactant is left after a given time, the calculator uses the integrated first-order rate law [A]t = [A]0·e^(−k·t). Provide the optional initial concentration [A]0 (in molarity) and a time t (in seconds) to evaluate the remaining concentration [A]t and the fraction remaining (e^(−k·t)). The mean lifetime, τ = 1/k, is the time at which the concentration falls to 1/e (about 37%) of its initial value.

Units must be consistent: k is given in 1/s and t in seconds here, so concentrations are reported in the same units as [A]0. The model assumes a single elementary first-order step at constant temperature with no reverse reaction. k must be positive; a zero or negative k is invalid because the half-life would be undefined or unphysical. The decay curve samples [A] versus time across roughly five half-lives, by which point about 97% of the reactant has been consumed.

Frequently asked questions

No. For a first-order reaction the half-life t½ = ln(2)/k depends only on the rate constant, so it is constant regardless of how much reactant you start with.

For a first-order reaction k has units of inverse time. This calculator uses 1/s, so times are in seconds. If your k is in 1/min or 1/hr, convert it (or your time) to keep units consistent.

It uses the integrated rate law [A]t = [A]0·e^(−k·t). After one half-life half remains, after two half-lives a quarter remains, and so on.

Also known as

first order half life
half life calculator
integrated rate law
exponential decay
rate constant
first order kinetics
first order half life calculator
half life first order

APA

TG we-Calculate Editorial Team. (2026). First-Order Half-Life Calculator [Online calculator]. TG we-Calculate. https://we-calculate.com/calculator/first-order-half-life-calculator

Chicago

TG we-Calculate Editorial Team. "First-Order Half-Life Calculator." TG we-Calculate. 2026. https://we-calculate.com/calculator/first-order-half-life-calculator.

IEEE

TG we-Calculate Editorial Team, "First-Order Half-Life Calculator," TG we-Calculate, 2026. [Online]. Available: https://we-calculate.com/calculator/first-order-half-life-calculator

BibTeX

@misc{wecalculate_first_order_half_life_calculator, title = {First-Order Half-Life Calculator}, author = {{TG we-Calculate Editorial Team}}, howpublished = {\url{https://we-calculate.com/calculator/first-order-half-life-calculator}}, year = {2026}, note = {TG we-Calculate} }

Did this calculator help you?