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First-Order Half-Life Calculator

Compute the half-life and remaining concentration of a first-order reaction from its rate constant.

1/s

First-order rate constant (must be positive)

M

Optional starting concentration

s

Optional time to evaluate [A]t
Half-life (t½)
13,8629s

Time for the concentration to fall by half

Rate constant k
0,05 1/s
[A] at time t
0,3679 M
Fraction remaining
36,79 %
Mean lifetime (1/k)
20 s
Concentration decay over ~5 half-lives
Step by step
  1. 1

    ln(2)

    0,6931
    The natural logarithm of 2 appears because the concentration falls by half each half-life.
  2. 2

    Half-life t½ = ln(2) ÷ k

    0,6931 ÷ 0,05 = 13,8629
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Miten tämä laskin toimii?

For a first-order reaction the half-life is t½ = ln(2)/k ≈ 0.693/k and depends only on the rate constant, not the starting amount. The remaining concentration after time t follows [A]t = [A]0·e^(−k·t). Enter k (and optionally [A]0 and t) to get the half-life, remaining concentration, and a decay curve.

Kaava
t½ = ln(2) / k = 0.693 / k ; [A]t = [A]0 · e^(−k·t)
How this is calculated

A first-order reaction has a rate that is directly proportional to the concentration of a single reactant. Its half-life depends only on the rate constant k (in inverse seconds), not on the starting concentration, so each successive half-life takes the same amount of time. The half-life is t½ = ln(2)/k ≈ 0.693/k. Enter k to get the half-life directly.

To find how much reactant is left after a given time, the calculator uses the integrated first-order rate law [A]t = [A]0·e^(−k·t). Provide the optional initial concentration [A]0 (in molarity) and a time t (in seconds) to evaluate the remaining concentration [A]t and the fraction remaining (e^(−k·t)). The mean lifetime, τ = 1/k, is the time at which the concentration falls to 1/e (about 37%) of its initial value.

Units must be consistent: k is given in 1/s and t in seconds here, so concentrations are reported in the same units as [A]0. The model assumes a single elementary first-order step at constant temperature with no reverse reaction. k must be positive; a zero or negative k is invalid because the half-life would be undefined or unphysical. The decay curve samples [A] versus time across roughly five half-lives, by which point about 97% of the reactant has been consumed.

Usein kysytyt kysymykset

No. For a first-order reaction the half-life t½ = ln(2)/k depends only on the rate constant, so it is constant regardless of how much reactant you start with.

For a first-order reaction k has units of inverse time. This calculator uses 1/s, so times are in seconds. If your k is in 1/min or 1/hr, convert it (or your time) to keep units consistent.

It uses the integrated rate law [A]t = [A]0·e^(−k·t). After one half-life half remains, after two half-lives a quarter remains, and so on.

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APA

TG we-Calculate Editorial Team. (2026). First-Order Half-Life Calculator [Online calculator]. TG we-Calculate. https://we-calculate.com/fi/calculator/first-order-half-life-calculator

Chicago

TG we-Calculate Editorial Team. "First-Order Half-Life Calculator." TG we-Calculate. 2026. https://we-calculate.com/fi/calculator/first-order-half-life-calculator.

IEEE

TG we-Calculate Editorial Team, "First-Order Half-Life Calculator," TG we-Calculate, 2026. [Online]. Available: https://we-calculate.com/fi/calculator/first-order-half-life-calculator

BibTeX

@misc{wecalculate_first_order_half_life_calculator, title = {First-Order Half-Life Calculator}, author = {{TG we-Calculate Editorial Team}}, howpublished = {\url{https://we-calculate.com/fi/calculator/first-order-half-life-calculator}}, year = {2026}, note = {TG we-Calculate} }

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