Beginner

Specific Heat (Q = mcΔT) Calculator

Find the heat energy required to change a substance’s temperature, or solve for mass, specific heat or temperature change using Q = mcΔT.

Solve for

Pick the unknown variable

kg

J/kg·K

Water ≈ 4186 J/kg·K

K

ΔT = T2 − T1 (same size in K or °C)
Heat energy Q
83 720J

Using Q = m·c·ΔT

Heat energy Q
83 720 J
Heat energy Q
83,72 kJ
Heat energy Q
20 009,56 cal
Mass m
2 kg
Specific heat c
4 186 J/kg·K
Temperature change ΔT
10 K
Joules83 720 J
Kilojoules83,72 kJ
Calories20 009,56 cal
Step by step
  1. 1

    Mass × specific heat

    2 × 4 186 = 8 372
  2. 2

    Heat energy Q = (m·c) × ΔT

    8 372 × 10 = 83 720 J
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Miten tämä laskin toimii?

Heat energy is Q = m·c·ΔT: multiply mass (kg), specific heat (J/kg·K), and temperature change. The result is in joules, also shown as kJ and calories. Switch the "Solve for" selector to instead find mass, specific heat, or ΔT from a known Q. It assumes one phase and constant c.

Kaava
Q = m × c × ΔT (ΔT = T2 − T1); kJ = Q / 1000; cal = Q / 4.184
How this is calculated

This calculator applies the fundamental calorimetry relation Q = m·c·ΔT, where Q is heat energy in joules, m is mass in kilograms, c is the specific heat capacity in joules per kilogram per kelvin (J/kg·K), and ΔT is the temperature change. The temperature change can be entered directly or computed as T2 − T1; because a kelvin and a Celsius degree are the same size, ΔT is identical whether you work in K or °C.

Use the "Solve for" selector to rearrange the equation for any unknown: m = Q/(c·ΔT), c = Q/(m·ΔT), or ΔT = Q/(m·c). The result is reported in joules and also converted to kilojoules (kJ = Q/1000) and thermochemical calories (cal = Q/4.184). A positive Q means heat is absorbed (temperature rises); a negative Q means heat is released (temperature falls).

The model assumes a single phase with constant specific heat over the temperature range and no phase change (melting or boiling), which would require additional latent-heat terms. To avoid division by zero, the calculator returns no result when a denominator (c·ΔT, m·ΔT, or m·c) is zero.

Usein kysytyt kysymykset

Mass in kilograms, specific heat in J/kg·K, and temperature change in kelvin (numerically equal to °C). The resulting Q is in joules, also shown in kJ and calories.

A negative Q means ΔT is negative — the substance cooled (T2 < T1) — so heat was released rather than absorbed.

No. Q = mcΔT covers heating within a single phase only. Phase changes need latent heat (Q = mL) added separately.

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APA

TG we-Calculate Editorial Team. (2026). Specific Heat (Q = mcΔT) Calculator [Online calculator]. TG we-Calculate. https://we-calculate.com/fi/calculator/specific-heat-calculator

Chicago

TG we-Calculate Editorial Team. "Specific Heat (Q = mcΔT) Calculator." TG we-Calculate. 2026. https://we-calculate.com/fi/calculator/specific-heat-calculator.

IEEE

TG we-Calculate Editorial Team, "Specific Heat (Q = mcΔT) Calculator," TG we-Calculate, 2026. [Online]. Available: https://we-calculate.com/fi/calculator/specific-heat-calculator

BibTeX

@misc{wecalculate_specific_heat_calculator, title = {Specific Heat (Q = mcΔT) Calculator}, author = {{TG we-Calculate Editorial Team}}, howpublished = {\url{https://we-calculate.com/fi/calculator/specific-heat-calculator}}, year = {2026}, note = {TG we-Calculate} }

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